What is the first step when rewriting y = 6×2 + 18x + 14 in the form y = a(x – h)2 + k?

16 must be factored from 18x + 14

x must be factored from 6×2 + 18x

6 must be factored from 6×2 + 14

6 must be factored from 6×2 + 18x

**the answer is :**

A quadratic equation has the general form of:

y=ax² + bx + c

It can be converted to the vertex form in order to determine the vertex of the parabola. It has the standard form of:

y = a(x+h)² – k

where h and k represents the vertex, h represent the point in the x axis and k is the point in the y axis. From the choices given, the first step in rewriting the equation is that 6 must be factored from 6×2 + 18x. Which yields to:

y = 6(x^2 + 3x) + 14.

In variable based math, * a quadratic condition* (from the Latin quadratus for “square”) is any condition having the shape

{\displaystyle ax^{2}+bx+c=0} ax^2+bx+c=0

where x speaks to an obscure, and a, b, and c speak to known numbers with the end goal that an isn’t equivalent to 0. In the event that a = 0, at that point the condition is straight, not quadratic. The numbers a, b, and c are the coefficients of the condition, and might be recognized by calling them, individually, the quadratic coefficient, the straight coefficient and the consistent or free term.

Since the quadratic condition includes just a single obscure, it is called “univariate”. The quadratic condition just contains forces of x that are non-negative numbers, and accordingly it is a polynomial condition, and specifically it is a moment degree polynomial condition since the best power is two.

Quadratic conditions can be unraveled by a procedure referred to in American English as calculating and in different assortments of English as factorizing, by finishing the square, by utilizing the quadratic equation, or by charting. Answers for issues comparable to the quadratic condition were referred to as ahead of schedule as 2000 BC